Identifying Redox Reactions

Redox

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Chem with Niwatori-san! =p

well so far we covered our unit learning as quoted by Antony-san
Ternary Nomenclature: Acids and Bases
Solubility
Identification of Unknown Solutions
Equations: Ionic, Net Ionic
Concentration, Titration, Neutralization
Moles, Volume




so from here we cleared a unit woo now we got 5 more units to cover so now is the time to pick up the pace people! Let's work hard in the future travels in chemistry!

This unit was finished today with a Test so hopes for the people who missed it come to Ms . K right away and ask for that test somehow!


LABS LABS LABS until we get into our heads as scientists we are hah! Better leave that to Ms. Kozoriz while we just do the experiments and the work included. Oh yeah next time let me get a scribe role where it isn't the test day people -_- dude this is like my second Test scribe once for physics now one for chem jeez what a coincidence huh? -_-

Oh well... luck of the draw.. =p

GAMBETE PEOPLE!! (gambete japanese for go for it! or work hard!)

next scribe is AngelaG *clap clap clap* (passes baton to her) "have fun!" ^o^

Where is the Next Blogger?

Okay, so since no one is blogging....

I'll blog for today...

We had a test today(again..:-)) about:

Ternary Nomenclature: Acids and Bases
Solubility
Identification of Unknown Solutions
Equations: Ionic, Net Ionic
Concentration, Titration, Neutralization
Moles, Volume

.....Titration Lab.....

Helooooooooo!!!!!

Today, we continue to answer the following questions on the titration lab booklet.

The purpose of this lab is to determine the unknown concentration of substances.


Photo of concentration of sodium hydroxide to a test tubes containing a known concentration on sulfuric acid until it becomes pink.

And last but not the least a short video about the titration......lab
CLICK HERE....
i guess i have nothing 2 say.



Well, DON't FORGET 2 answer the booklet it's due TOMORROW.







NEXT SCRIBE IS................Niwatori-san......

Titrtation Lab

Hello...

Okay, so what we did today (and also learned) is the Titration Reaction (Lab. or Experiment...)

Titrations are procedures which are usually used to determine the unknown concentrations of substances . It is a common laboratory method of quantitative/chemical analysis that can be used to determine the unknown concentration of a known reactant. Because volume measurements play a key role in titration, it is also known as volumetric analysis. A reagent, called the titrant, of known concentration (a standard solution) and volume is used to react with a solution of the analyte, whose concentration is not known in advance. Using a calibrated burette to add the titrant, it is possible to determine the exact amount that has been consumed when the endpoint is reached. The endpoint is the point at which the titration is complete, as determined by an indicator.

THE EXPERIMENT
Materials: 1-50mL beaker
3 Micropipettes
Phenolphthalein Indicator
10 mL Graduated Cylinder
Distilled Water
0.1 mol/L NaOH
0.1 mol/L H2SO4


Procedures:

1.) Using the Graduated Cylinder and a micropipette, count and record the number of dropd required to obtain 1.0 mL of distilled water. REPEAT the process 3 TIMES.

2.) Add 5 mL of Distilled water, and 1 drop of Phenolphthalein Indicator to the 50 mL beaker.

3.) Using a 2nd micropipette, add 20 drops of 0.1 mol/L H2SO4 to the beaker.

4.) Using the 3rd micropipette, add the 0.1 ml/L NaOH drop by drop until the addition of one drop permanently changes the colour of the solution. Recprd the number of drops required to reach the endpoint of tartration.

5.) Rinse the contents of the beaker. "Repeat Steps 2-4 a total of 3 times!!!!"

The Next 'Blogger' is M:-)

Two Days Befor My Birthday!! a.k.a sep 16th :)

OK SO todayyyy we looked at page 7 in the YELLOW booklet thing.

Page 7:

What volume of a 0.250 ml/L solution of carbonic acid is needed to neutralize 30.0g of sodium hydroxide?
Q1: write the nutralization reaction
A1: H2CO3 (aq) + 2NaOH -> Na2CO3(aq) + 2H2O(s)
Q2: Determine the number of moles of base.
A2: 30g NaOH x (1mol NaOH/40g NaOH) = .75 mol NaOH
Q3: Calculate moles of H2CO3 Needed to neutralize the base.
A3: 1mol acid 2 mol base
.375 mol acid .75 mol base
Q4: Calculate the volume of H2CO3 required
A4: V=n/c = (.375 mol H2CO3)/(.250 mol H2CO3)
V=1.5 H2CO3(aq)

WE ALSO GOT a NEw booklet on Neutralization Reactions and did the questions on the back of the booklet :D

It was overall a productive day andd personally, i don't understand what we covered ... But its not too too bad .

OH!!! AND we had a lock down in effect and ppl were yelling i the halls and so on so that was kinda the most interesting peek of the class :)


NEXT SCRIBE IS ***NCC-74656***

scribe post

Hey guys,

ok so today in class we learned how to Write Ionic and Net Ionic Equations.

Q: why is a "total ionic equation"?
A: Because every spieces which breaks down into it's ions when dissolved in water has been written in ionic form.

Q: What is a "net ionic eaquation"?:
A: an equation that includes only those compounds and ions that undergo a chemical change in a reation which occurs in aqueous solution; shows the reaction that occurs, omitting the spectator ions.

Vocbaulary:
Spectator: ions found in solutions both before and after a chemical reaction; they "watch" the reaction occur.
Salt: a compound composed of the negative ion of an acid and the positive ion of the bases.

so off the sheet Ms. Kozoriz gave us today titled:

"Summary of Writing Total Ionic and Net Ionic Equations"

it shows the 7 steps in writing these equations. These steps are:

STEP 1: identify type of reaction and possible products.

STEP 2: look up solubility of both products.

STEP 3: Indicate states of reactants and products.

STEP 4: Write chemical equations for reaction.

STEP 5: balance the equation.

STEP 6: Write total ionic equation.

STEP 7: Write Net Ionic Equation.
(on that sheet we are given two different examples which follow these steps.)


WHAT IS NEUTRALIZATION?
Neutralization: a neutralization reaction is one whose products are a salt and a water.

aN equation such as:
ACID + BASE -----> SALT + WATER

CALCULATING AN UNKNOWN CONCENTRATION:
We would follow the 4 steps:

1) write the balanced neutralization reaction

2) calculate the number of moles of the solution. (stoichiometry)

3) calculate the moles of acid/base used.

4) calculate the concentration of the acid/base.

Using the formula:

concentration = n / v (moles / volume)

We can solve questions to determine the amount of acid of base needed to neutralize the solution:

** calculate the concentration of hydrochloric acid, if 25.00 mL is just neutralized by 40.00 mL of a 0.150 mol/L sodium hydroxide solution.



1) HCl(aq) + NaOH -----> H2O(l) + NaCL(aq)

2) (moles = c x v)
= 0.150 mol/L x 0.040L
= 0.006 mol NaOH

3) moles of HCl = moles of NaOH

4) (c = n / V)
= 25 mL x (1 L / 1000 mL) = 0.025 L
= 0.006 mol HCl / 0.025 L = 0.24 mol/L HCL

ok that's about it. i was working on the lab during class so i'm still reading over todays notes. so for anyone whose having problems if you don't get it try reading the notes it can be found in the yellow booklet (pages 4 - 6) and i believe i recall Ms. Kozoriz assigning page 7 for homework so just incase might wanna work on that!

the next scribe will be the_bdl